A 10.0 in main line needs to be flushed. If one volume of 310 ft section of the pipeline was flushed through a fire hydrant for 15 min, what was the flushing rate in gallons per minute?

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Multiple Choice

A 10.0 in main line needs to be flushed. If one volume of 310 ft section of the pipeline was flushed through a fire hydrant for 15 min, what was the flushing rate in gallons per minute?

Explanation:
Flushing rate is the volume moved per unit time, so start by finding how much water sits in the 310 ft section of the 10-inch main and then divide by the flush duration. Convert diameter to feet: 10 inches is 0.8333 ft, so the radius is 0.4167 ft. The cross-sectional area is πr^2 ≈ 0.545 ft^2. Multiply by the length to get the volume: 0.545 ft^2 × 310 ft ≈ 168.95 ft^3. Convert to gallons: 1 ft^3 = 7.4805 gal, so the volume is about 168.95 × 7.4805 ≈ 1,263.6 gallons. Flushing for 15 minutes gives a rate of 1,263.6 gallons / 15 min ≈ 84.2 gpm. So the flushing rate is about 84 gpm. The given options don’t match this result, suggesting an error in the listed choices.

Flushing rate is the volume moved per unit time, so start by finding how much water sits in the 310 ft section of the 10-inch main and then divide by the flush duration.

Convert diameter to feet: 10 inches is 0.8333 ft, so the radius is 0.4167 ft. The cross-sectional area is πr^2 ≈ 0.545 ft^2. Multiply by the length to get the volume: 0.545 ft^2 × 310 ft ≈ 168.95 ft^3. Convert to gallons: 1 ft^3 = 7.4805 gal, so the volume is about 168.95 × 7.4805 ≈ 1,263.6 gallons. Flushing for 15 minutes gives a rate of 1,263.6 gallons / 15 min ≈ 84.2 gpm.

So the flushing rate is about 84 gpm. The given options don’t match this result, suggesting an error in the listed choices.

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