If 18 lb soda ash are mixed with 75 gal water, what is the slurry concentration when the water volume is increased to 150 gal while keeping 18 lb?

Prepare for the Washington State WDM 1 with flashcards, multiple choice questions, hints, and explanations. Get exam ready now!

Multiple Choice

If 18 lb soda ash are mixed with 75 gal water, what is the slurry concentration when the water volume is increased to 150 gal while keeping 18 lb?

Explanation:
Slurry concentration by weight is the mass of solids divided by the total slurry mass (solids plus liquid), expressed as a percentage. First, find the weight of the water at 150 gallons: 150 gal × 8.34 lb/gal ≈ 1251 lb. Add the solids: 1251 lb + 18 lb = 1269 lb total slurry. The solids fraction is 18 lb / 1269 lb ≈ 0.01417, which is about 1.4%. Doubling the water while keeping the same solids lowers the concentration roughly by half, from about 2.8% (with 75 gallons) to about 1.4% (with 150 gallons). Thus, the appropriate slurry concentration is approximately 1.4%.

Slurry concentration by weight is the mass of solids divided by the total slurry mass (solids plus liquid), expressed as a percentage.

First, find the weight of the water at 150 gallons: 150 gal × 8.34 lb/gal ≈ 1251 lb. Add the solids: 1251 lb + 18 lb = 1269 lb total slurry. The solids fraction is 18 lb / 1269 lb ≈ 0.01417, which is about 1.4%.

Doubling the water while keeping the same solids lowers the concentration roughly by half, from about 2.8% (with 75 gallons) to about 1.4% (with 150 gallons). Thus, the appropriate slurry concentration is approximately 1.4%.

Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy