What is the hydrostatic pressure at the base in pounds per square foot due to a groundwater head of 7.15 ft?

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Multiple Choice

What is the hydrostatic pressure at the base in pounds per square foot due to a groundwater head of 7.15 ft?

Explanation:
Hydrostatic pressure from a water column grows in proportion to depth, calculated as the unit weight of the water times the depth. For freshwater, the unit weight is about 62.4 lb/ft^3. So at a groundwater head of 7.15 ft, the base pressure is 62.4 × 7.15 = 446.16 psf. This is pounds per square foot, since lb/ft^3 times ft gives lb/ft^2. The result 446.16 psf matches the given value.

Hydrostatic pressure from a water column grows in proportion to depth, calculated as the unit weight of the water times the depth. For freshwater, the unit weight is about 62.4 lb/ft^3. So at a groundwater head of 7.15 ft, the base pressure is 62.4 × 7.15 = 446.16 psf. This is pounds per square foot, since lb/ft^3 times ft gives lb/ft^2. The result 446.16 psf matches the given value.

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