What is the internal surface area value of the cylindrical tank with diameter 65 ft and height 24 ft?

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Multiple Choice

What is the internal surface area value of the cylindrical tank with diameter 65 ft and height 24 ft?

Explanation:
Internal surface area of a closed cylinder comes from the curved side plus both circular ends. So calculate the radius from the diameter: r = 65/2 = 32.5 ft, height h = 24 ft. Curved surface area = 2πrh = 2π × 32.5 × 24 = 1560π ft^2. End caps area = 2πr^2 = 2π × (32.5)^2 = 2112.5π ft^2. Total internal surface area = 1560π + 2112.5π = 3672.5π ft^2 ≈ 1,152.5 × π ≈ 11,537 ft^2. The closest option is about 11,531.65 ft^2.

Internal surface area of a closed cylinder comes from the curved side plus both circular ends. So calculate the radius from the diameter: r = 65/2 = 32.5 ft, height h = 24 ft.

Curved surface area = 2πrh = 2π × 32.5 × 24 = 1560π ft^2.

End caps area = 2πr^2 = 2π × (32.5)^2 = 2112.5π ft^2.

Total internal surface area = 1560π + 2112.5π = 3672.5π ft^2 ≈ 1,152.5 × π ≈ 11,537 ft^2.

The closest option is about 11,531.65 ft^2.

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